Reroll or failure = specific number

im wating to make a macro that rolled 3d6 but 1 and 2 become 3  kinda like 1d6r<2 but the rerolls are automatic 3's

You probably need to look into making a rollable table, with items: 3, weight 3, and items 4, 5, 6 each having weight 1.

ok thanks! 

A rollable table would be easier and cleaner, but you could do either one of these: [[ [[{1d6,3d1}kh1]] + [[{1d6,3d1}kh1]] + [[{1d6,3d1}kh1]] ]] = $[[0]] + $[[1]] + $[[2]] [[ [[{[[1d6]],3}kh1]] + [[{[[1d6]],3}kh1]] + [[{[[1d6]],3}kh1]] ]] = $[[1]] + $[[3]] + $[[5]]

Oh yes, so you can. If you used a rolltemplate, you could expand Jarren's sugggestion by hiding the working section and put the roll total after the individual parts. Here's a quick and dirty example: &{template:default} {{name=ROLL TITLE}} [[ [[{1d6,0d0+3}kh1]] + [[{1d6,0d0+3}kh1]] + [[{1d6,0d0+3}kh1]] ]] {{dice=$[[0]] + $[[1]] + $[[2]]}} {{total=$[[4]]}} I used a slightly different roll than Jarren, because its the one I prefer for these situations. I think it's a little less laggy.