Is there a round() function for macros?

Is there a function for macros similar to ceil() and floor() that just does a normal round? If not, I think this would be a great addition. Consider the following macro: [[d20+0.25*@{STR}]] This macro will print out a decimal response not very useful for most RPGs: e.g. 10.25 If I use ceil(): [[d20+ceil(0.25*@{STR})]] then a player with 1STR incorrectly gets the same bonus as someone with 4STR. Using floor() results in a similar problem. A round() function would be a simple addition that would fit nicely with the ceil() and floor() functions.

Wow, after some guessing, it appears that there actually is a round() function, it is just not documented anywhere I could find it. I suggest that a dev add it to the Dice Reference . For others who may stumble across this post: [[round(1.25)]] = 1 [[round(1.5)]] = 2 [[round(1.75)]] = 2

Cool. Nice discovery! :)

John said: I suggest that a dev add it to the Dice Reference . Why don't you? =)

I have added it to the Dice Reference.

I was looking around the other day for something like this. Nice find. I can also add a little bit to this. If you have a fraction for a formula determining how many die to roll, it seems to round up automagically. For instance, I was making a macro to calculate my Channel Positive Energy die using this macro: Where Level is the character's channeling level; /roll (@{Selected|Level}/2)d6 of damage. Thus, when Level=1, it yielded a 1d6 roll, Level=3 yields 2d6 and so-on. I'm not sure if this is an official rounding function, or just an unintended side effect hat could change?

Ryan P. said: If you have a fraction for a formula determining how many die to roll, it seems to round up automagically. Actually, the system uses round-to-nearest, not round-up when determining the number of dice to use. After all, rolling half of a die makes no sense*. Your example will always be rounding up because you're dividing by 2, which will always result in a 0.5 fractional part, which is rounded up with round-to-nearest. However, if you tried a formula which was dividing by 3, you'd see that it also rounds down when appropriate. =) * Unless you're Cohen the Barbarian trying to roll a 7 on a 6-sided die.

There are floor and ceiling functions, as well.

John was aware of floor and ceil, but he wanted round. =)