[Help] Proper IF syntax

Context: I am a gamer with an understanding of the very basics of coding. Situation: I am working on modifying the API script "The Darkness Is Closing In" to check for whether the character has the "All Players See Light" checkbox checked. The unaltered script is: on("change:token", function(obj, prev) { //Only do this if we actually moved. if(obj.get("left") == prev["left"] && obj.get("top") == prev["top"]) return; obj.set({ light_radius: Math.floor(obj.get("light_radius") * 0.90) }); }); Issue: I am unable to properly format the new IF line. The plain language is: "If All Players See Light property is false, then return (don't execute the remainder of the script). This is what I currently have written that is not correctly catching the instance where the condition where property is false (unchecked): on("change:token", function(obj, prev) { //Only do this if we actually moved. if(obj.get("left") == prev["left"] && obj.get("top") == prev["top"]) return; if(obj.get("light_otherplayers") !== false) return; obj.set({ light_radius: Math.floor(obj.get("light_radius") * 0.90) }); }); Any assistance as to the proper syntax would be appreciated.

The sense of your statement is opposite of the behavior you described: "!==" means "is not identical to", so you're taking the early exit if the "light_otherplayers" property is not "false". You want "===" (really, you probably want "==", because you probably want to take the early exit for all falsey values -- e.g. 0, "", null, etc. -- not just false).

So, with Manveti's thoughts: on("change:token", function(obj, prev) { //Only do this if we actually moved. (and all players see light) if( (obj.get("left") == prev["left"] && obj.get("top") == prev["top"]) || !obj.get("light_otherplayers")) { return; } obj.set({ light_radius: Math.floor(obj.get("light_radius") * 0.90) }); });

Excellent. That did it.