[Fantasy Age] How does one seperate the Stunt Die?

I have a burning question. Is it possible to designate a "stunt die" in the three six-sided dice you roll in the interface of Roll 20?

Sure you can. You manipulate the critical failure & critical success numbers for each roll. Like this: [[1d6cs>7cf<0]] [[1d6cs>7cf<0]] [[1d6cs>1cf<6]] You will always get 2 black dice and 1 blue die. 

You mean something like the Wild Die in WEG Star Wars?  I think you just have to roll a separate D6 for that.  I'm ignorant about the whole API thing, though, so hopefully the resident API wizards will have a better answer for you.  I haven't come across any dice macros that will do it.

Well, there you go.  I stand corrected (Didn't see Andrew's post before I responded).

We always just pick one of the 3 dice in the 3d6 array to be the stunt die, it's not fancy but there it is. (In the campaign I'm currently in we've designated the last die on the right to be the stunt/action/dragon die). I think it'd be nice if you could get a highlight for doubles/triples in the way that critical failure/successes light up. (Currently you'd probably need to apply an API script to the problem)  That way you could have the collapsed rolls in macros and templates with a visual reminder to hover over the roll to see if you stunted or not.