[3.5e] Receiving half point bonus D&D 3.5 Concentration skill

Hello, I am using the built-in D&D 3.5 character sheet and when I use the roll template for some skills (Concentration in this case) I am receiving a 10.5 bonus. I have this marked as a class skill (via the checkbox next to the skill). The entries I have are: Total Bonus: 10 Stat: Con Ability Mod.: 0 Ranks: 7 Misc. Mod: 3 Notes:&nbsp;+3 psycrystal Macro:&nbsp;&{template:DnD35StdRoll} {{skillflag=true}} {{name=@{character_name} }} {{check=[Concentration](<a href="http://www.dandwiki.com/wiki/SRD:Concentration_Skill" rel="nofollow">http://www.dandwiki.com/wiki/SRD:Concentration_Skill</a> ) check:}} {{checkroll=[[1d20 + [[@{concentration}]] ]] }} Any idea why my bonus to this skill is 10.5?

Moving to the Character Sheets forum

Is your Constitution 11? I'll bet the sheet isn't rounding down the ability modifier.

The ability score should be calculating correctly; the formula should have a floor in it. &nbsp; I have not had reports of any kind of systemic issues with skill calculations so as far as I know the base calculations are correct. &nbsp;Unfortunately, I'm away from my computer at the moment. &nbsp;I can look into trying to figure out what's up next week when I get back home.

My constitution is indeed 11.

Ok, I've had some time to try and reproduce your issue, but I cannot reproduce it.&nbsp; Was the character affected one which existed prior to adding the character sheet template to the campaign? The formula on the sheet calculates the ability bonus as floor(ability/2)-5 .&nbsp; Try looking on the built-in Abilities and Attributes tab for either a con-mod or a conmod attribute (of a .5) and deleting it.&nbsp; The ones calculated by the character sheet should not show up there since they are calculated values and having a manually entered attribute of that name could cause the symptoms you are seeing. Hope that helps.

Right, thanks for the reply. That was the problem. Not the equation on any of the ability modifiers: previous:&nbsp;[[(@{con}-10)/2]] new:&nbsp;[[floor((@{con}-10)/2)]]