Dice macro (Roll 1d10 with a min off 4)

I was wondering if there was a way to roll a dice and have the minimum off said dice be x amount (in this case rolling 1d10 and not being able to get lower then 4).  ((Should also most likely have included in the title that it was a question, not a actual macro. My apologize))

Yes this is possible {1d10, 4+0d0}kh1 See the  Dice Reference for more information.

How exactly do you chain this together? As in rolling 6d10 with a minimum off 4 and killing the lowest 3. Thanks for the quick awnser btw. Edit: What im trying to do is roll 6d10 with a minimum off 4 and kill the lowest 3 dice rolls then add a +13 and have the end result be organized from highest to lowest 

In this system, do you treat all results below 4 as 4? If so, the simplest way would be to use a table, probably, with entries 4,4,4,4,5,6,7,8,9,10. If you ignore results below 4 and keep rolling till you get between 4 and 10, then you can use 1d7+3. Otherwise, just type out the expression kyle gave as many times as you need: /roll {1d10, 4+0d0}kh1 + {1d10, 4+0d0}kh1 + {1d10, 4+0d0}kh1 + {1d10, 4+0d0}kh1 + {1d10, 4+0d0}kh1 + {1d10, 4+0d0}kh1

The main problem is is that I need to roll 6d10 with a minimum off 4, have the 3 lowest be killed, add a +13, and then order them from highest to lowest. I might and most likely am just doing something wrong, but neither thing seems to work. Edit: 6d10sdkh3+13 That is the closet thing I have been able to get so far, but that still does not have the minium 4 out off 10 thing build inside off it. Thanks for all off the help and quick replys btw.

Your best bet might be to make a rollable table then. Call it d10min4 Value Weight 4 4 5 1 6 1 7 1 8 1 9 1 10 1 Then for your roll you would use {6t[d10min4}kh3+13. This is the how it would look in the chat. Unfortunately I was unable to find a way to order the values using either this method or the grouping method ({1d10,4+0d0}kh1).

I dont know how to make a rollable table, I am also not the DM.

MysticDragon said: I dont know how to make a rollable table, I am also not the DM. Ok then you will have to do the grouping method. {{1d10,4+0d0}kh1,{1d10,4+0d0}kh1,{1d10,4+0d0}kh1,{1d10,4+0d0}kh1,{1d10,4+0d0}kh1,{1d10,4+0d0}kh1}kh3+13 It is certainly not as pretty as the table method.

How would a table have to be added? I could always ask the DM nicely Once again thanks for the help

Point your DM here&nbsp;<a href="https://wiki.roll20.net/Collections#Rollable_Tables" rel="nofollow">https://wiki.roll20.net/Collections#Rollable_Tables</a>

Alright, thank you all for the help.

Hi there, I may be missing something but wouldn't [[{6d10r1r2r3sd}kh3+13]] work (rolls 6d10 with a minimum die value of 4, retains the 3 highest rolls, then orders them), however I'm unsure what to do with an inline roll if you want to add 13 to each of the die. [[{(1d10r1r2r3+13),(1d10r1r2r3+13),(1d10r1r2r3+13),(1d10r1r2r3+13),(1d10r1r2r3+13),(1d10r1r2r3+13)}kh3]] may work but is messy and then it wont sort them...

A problem I can see with that approach is the chance to get a value greater than 4 is much higher (you are essentially turning a d10 into a d7 + 3)

Once again thanks for all the helpful people, and you are correct Kyle did not think off that, haha. Cheaty little derg over here :P