Roll d6 for successes, -1 for every pair of 1's rolled

I understand how to roll for successes. For my game it is: /roll #d6>4 I can get by with that, visually and verbally calculating all 1's that pop up. For every pair of 1's, a -1 is applied to the resulting number of successes. Is there a way to automatically do this? Thank you for taking the time to read this, Roll20 calculator wizards.

There's no way for a free user to do this. Pro users have access to the scripting API which would let someone write a script to achieve it, but it's still a bit complex if you arent skilled with javascript. What you can do is have the dice sorted automatically, something like  /roll #d6 sd >4  which will group the ones together and make it easier to count them. sd  means stort descending. Highest values come first. If you want to sort the other way, use sort ascending: /roll #d6 sa >4  By the way, just in case you aren't aware, in roll20 >4  means all results equal to or greater  than 4. If your system counts successes on 5 and 6 only, you'll need to change that to >5 .

Thank you so much, G G! This is great information. Aye, 4, 5, and 6 are successes. We've played already, and I kept thinking 5 and 6 were successes because of Shadowrun =P I think we will incorporate sort-ascending, as we need to pay attention to the 1's.