How to count dice over a certain a number?

Is there anyway of counting dice only over a certain number? 1-2=0 3-4=1 5-6=2.

You could make a six-sided roll-able table and have the "sides" go 0,0,1,1,2,2. <a href="https://wiki.roll20.net/Card_Decks_and_Rollable_Ta" rel="nofollow">https://wiki.roll20.net/Card_Decks_and_Rollable_Ta</a>...

roll a 3 sided die instead of a six 1=0 2=1 3=0 it's a no brainer

1 and 6 are crits...Not a no brainer.

I realize it's the more complicated option, but with the rollable tables you would get your six sided die, and if you use images for the 'faces' you could make 0 and 2 different to illustrate the Crit.

Ok So im working on the table. Almost got it how I want. On a roll 6 I get to roll another die. Is there anyway of doing this with a table? Besides that it looks like I just have crit next to 1 and 6 that equal 0 and 2. So I can tell they critted.

I don't know if it'd work or not so you have to test, but you may be able to combine rollable tables and exploding dice.(If you roll max value and it rolls again) <a href="https://wiki.roll20.net/Dice_Reference#Exploding_D" rel="nofollow">https://wiki.roll20.net/Dice_Reference#Exploding_D</a>... /roll 1t[table-name]!

Sadly tables do not support exploding dice. If you get a 6 on your result, you'll need to make a new table roll. What you could do is decide how many explosions to want, and then create a table with the full range of possibilities using the weighting entry. For instance, if on a roll of 6, you get an extra d6 added to it, that would look like this: Result Weighting 1 6 2 6 3 6 4 6 5 6 7 1 8 1 9 1 10 1 11 1 12 1 I know that's not how it works in your game; this example is just to illustrate the concept.

Ya except if you get multiple 6s it wouldnt work...Ill just keep doing what im doing I suppose.

Well could go three steps into it, to 66x, that's 18 possibilities. Should be more or less easy enough to do. IF someone actually rolls a 666 on that table... (1 in 216 rolls), they just have to hit the macro again. Or you go 4 steps in. 6666 is a 1 in 1296 chance, that should be good enough.

Ya. Ill think about it. 1296 entries would take some time. lol

You dont actually need 1296 entries. For example, if you were rolling 3d6 and adding then together, there are 216 different ways the dice can fall, but you only need 16 different table entries. Describe how the dice work in your game and I'll tell you how to make a short table that represents that.