Need help with inline macro

I'm trying to pull a stat off a D&D 4e character sheet, divide it by a certain amount, and then use that amount to determine how many of the Fate/fudge dice to roll. I'd like to do it as an inline roll, but I can't get it to work. I'm using the floor() function to get a whole number for the dice roll, but it won't actually do the dice roll unless I type it in funky, aka not as an inline roll, just inline calculations. I have a character named Nick's Fighter, he has a strength attribute of 18 (this can be referenced by @{Nick's Fighter|strength} which spits out the proper number when I do the inline command like this - [[@{Nick's Fighter|strength}]] which gives the little box with 18 in it), and I need to divide that attribute by 5. That should give me 3, and I want to roll that many fate dice. This is what I tried at first, but it gave me an error. (Could not determine result type of: [{"type":"M","expr":"floor(18/5)"},{"type":"C","text":"df"}]) [[floor(@{Nick's Fighter|strength}/5)df]] This is the only way I can get it to work. /r [[floor(@{Nick's Fighter|strength}/5)]]df What am I missing to get it all inline?

Try: [[ ((@Nick's Fighter|strength}-2.5)/5)df ]] The -2.5 will cause the rounding to skew to where it behaves as floor and get you the right number of dice.

Try (@{Nick's Fighter|strength} / 5 - 0.5)df The number of dice is automatically rounded to the nearest whole number (because rolling a fractional number of dice doesn't make sense). To make sure your number doesn't get rounded up, subtract 0.5 from your initial result: 1.0 - 0.5 = 0.5 => 1 1.1 - 0.5 = 0.6 => 1 1.4 - 0.5 = 0.9 => 1 1.5 - 0.5 = 1.0 => 1 1.6 - 0.5 = 1.1 => 1 1.9 - 0.5 = 1.4 => 1

This also works: [[ ({floor(@{Nick's Fighter}/5)}kh1)df ]]

Aaron said: This also works: [[ ({floor(@{Nick's Fighter}/5)}kh1)df ]] I just get the number of dice (3) instead of the roll (3df).

Thanks guys, getting the results I'm wanting now! =D Really appreciate the speedy responses. You just made one flustered DM that much less stressed about running his game.

Brian -- You're right, that second method doesn't work. I was so excited not to get the error that I forgot to check the results. =D Lake / James -- Glad to hear it!

Worth mentioning: Aaron's first method and my method are the same thing, mathematically. (X - 2.5) / 5 = X / 5 - 2.5 / 5 = X / 5 - 0.5