Problem with Math, subtraction and Dices

I don't know if this is possible, but I want a macro to calculate a differance between 2 ratings, but I don't want it to write a negative value. It's a simple subtraction (x-character appearance rating) Any ideas on how to achieve this? I suck at math

Solved! [[{{?{how much appearance does your mask have?|1}-@{selected|Appearance},0}>1}*([[?{how much appearance does your mask have?}-@{selected|Appearance}]]-0)+0]]

You can also do: [[ abs( ?how much appearance does your mask have?|1}-@{selected|Appearance} ) ]] See:&nbsp;<a href="https://wiki.roll20.net/Dice_Reference#Rounding_Rolls_and_Math_Functions" rel="nofollow">https://wiki.roll20.net/Dice_Reference#Rounding_Rolls_and_Math_Functions</a>

The Aaron said: You can also do: [[ abs( ?how much appearance does your mask have?|1}-@{selected|Appearance} ) ]] See:&nbsp; <a href="https://wiki.roll20.net/Dice_Reference#Rounding_Rolls_and_Math_Functions" rel="nofollow">https://wiki.roll20.net/Dice_Reference#Rounding_Rolls_and_Math_Functions</a> Just tried, but it didn't work as I was expecting.&nbsp; if the mask is 1 for exemple, and my character appearance rating 5, I wanted the problem to write 0, because that's the amount of blood points the discipline requires.

I don't know anything about the mechanics of the game you're playing.&nbsp; I'm just pointing out the existence of the abs() function for generating the unsigned result of some expression: [[ 1 - 5 ]] will be -4 [[ abs(1 - 5) ]] will be 4

The Aaron said: I don't know anything about the mechanics of the game you're playing.&nbsp; I'm just pointing out the existence of the abs() function for generating the unsigned result of some expression: [[ 1 - 5 ]] will be -4 [[ abs(1 - 5) ]] will be 4 Oh, I see. Tried this, but unfortunally it wasn't what I was looking for. I wasn't very clear in specifying that I wanted to write 0 in the chat when the result came back negative. Sorry, my bad.

here you go: [[{(A-B), 0}dl1]] Replace A and B with the two values. If negative it will drop the lowest and replace it with 0.&nbsp;

Gauss said: here you go: [[{(A-B), 0}dl1]] Replace A and B with the two values. If negative it will drop the lowest and replace it with 0.&nbsp; wtf, it worked perfectly and it is simpler. tell me how this works mr.wizard

(A-B)&nbsp; = the math you want {(A-B), 0}dl1 = tells the system to drop the lowest value between (A-B) and 0. IF A-B is a negative, it is the lowest value compared to 0.&nbsp; [[&nbsp; &nbsp;]]&nbsp; = just puts it in a nice neat answer format (box)

Gauss said: (A-B)&nbsp; = the math you want {(A-B), 0}dl1 = tells the system to drop the lowest value between (A-B) and 0. IF A-B is a negative, it is the lowest value compared to 0.&nbsp; [[&nbsp; &nbsp;]]&nbsp; = just puts it in a nice neat answer format (box) Niiice!