Community Forums: Sneak Attack Formula for Pathfinder Rogue?

Sneak Attack Formula for Pathfinder Rogue?

1407136416

I can't seem to figure out the proper formula to automatically calculate sneak attack damage for a rogue. This is what I have - [[floor(@{level}/2)d6]] but that gives a syntax error. Can anyone help me out?

1407137678

Lithl

Pro

Sheet Author

API Scripter

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Functions don't work before the 'd'. However, the number before the 'd' is automatically rounded to the nearest whole number. To ensure that you're rounding down, subtract something less than 0.5. For example: [[(@{level} / 2 - 0.1)d6]] ought to do the trick.

1407138955

Edited 1407138976

Gauss

Forum Champion

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For a Pathfinder rogue (1d6 every odd level) I suggest using (@{level}/2+0.1)d6 If the level is a "1" then it will produce a 1d6 (0.5+0.1)d6 = (0.6)d6 = 1d6 If the level is a "2" then it will produce a 1d6 (1 + 0.1)d6 = (1.1)d6 = 1d6 If the level is a "3" then it will produce a 2d6 (1.5 +0.1)d6 = (1.6)d6 = 2d6 and so on....

1407170587

Ryan L.

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Thanks guys!

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Sneak Attack Formula for Pathfinder Rogue?