Extremely frustrating error when trying to set a maximum value to a roll with a modifier

I'm trying to make a macro that rolls a character ability which does the following: Roll the character's base damage (a number of d6 (in this case, 3) with a modifier (in this case, +8)) and that number cannot be higher than half of the same character's Defense score (which is 23, halved to 11.5). In other words, roll 3d6+8 with a maximum of Defense/2. But this section of the macro is giving me issues: {{Damage=[[{(3d6+8)/2, 11.5}kl1]]}} It throws me this error: Cannot mix M and sum rolls in a roll group Changing 11.5 to @{Defense}/2 like I would prefer spits out the same error but the M and sum are reversed. I have absolutely no idea what to do about this. It is very annoying because nearly everything in the game I'm running works like this: Roll with a modifier and have a maximum cap on the result. Can I get some help? Perhaps a workaround?

Hi Lucifina,  The problem is you have a roll and a non-roll in the kl1 calculation.  There are two solutions.  1) Eliminate the roll, you can do this by enclosing it inside double inline brackets like this:  {{Damage=[[{(  [[ 3d6 ]]  +8)/2, 11.5}kl1]]}} 2) Add a roll, you can do this like this:  {{Damage=[[{(3d6+8)/2, 1d0+ 11.5}kl1]]}} I have bolded the changes in both versions. 

The problem is you have a roll and a non-roll in the kl1 calculation.  There are two solutions.  1) Eliminate the roll, you can do this by enclosing it inside double inline brackets like this:  {{Damage=[[{(  [[ 3d6 ]]  +8)/2, 11.5}kl1]]}} 2) Add a roll, you can do this like this:  {{Damage=[[{(3d6+8)/2, 1d0+ 11.5}kl1]]}} Thank you, I chose to go with method 1. Had no idea that would work or why it does.

Here is why it works {X,Y}k1 X and Y must both be a roll, or neither be a roll.  In the case of {1d6,15}k1 you have a roll and a non-roll. It won't work.  If you wrap 1d6 in inline brackets that rolls it before resolving the rest.  That gives us: {[[1d6]],15}k1 Because of [[ ]] the 1d6 is rolled before resolving the rest of the calculation. Lets assume it is a 3. That becomes {3,15}k1 Now neither are rolls and the {X,Y}k1 can work properly.