How to write a macro that rolls a D12 which fails if 1 or 7 or 11, else succeed

"How to write a macro that rolls a D12 which fails if 1 or 7 or 11, else succeed", everything is in the title So far I tried  [[{?{INPUT}d8>2f7f11}]] but Roll20 doesn't allow for two different failures...

If scripts are available, the Metascript Toolbox would approach it like this: !&{template:default} {{name=Proof of Concept}} {{Base Roll=[[15d12]] }} {{Showing Dice= {&eval}getDiceByVal(--$[[0]] --<13 --included --list|", "){&/eval}}} {{Failures={&eval}getDiceByVal(--$[[0]] --1|7|11 --included --count){&/eval} }} {{Successes={&eval}getDiceByVal(--$[[0]] --2-6|8-10|12 --included --count){&/eval} }}{&simple} If scripts are NOT available, there might be some dark sorcery Rainbow might be able to pull off, if you are willing to pay the price*. I'll see if I can summon them. * -- I am being told there's no actual price.

Are the dice roll values used for anything beyond determining success/failure? If not you can just use [[?{INPUT}d12>4]] as that is statistically equivalent. But if need to be able to read the values the closest you'd get would be [[ (?{INPUT}-[[?{INPUT}d12=11 ]])d12>2f7r11  That would show all the values correctly except 11's. But the correct number of 11's rolled would be visible at the start of the roll inside the ( ) as that would show (INPUT - Eleven's)