Floor inside of an inline roll

I'm not sure if what I am trying to accomplish is possible but I am trying to roll a number of dice that is variable to a character's level. I am using floor to remove the decimals as [[(3/2)d6]] will roll 2 dice. However when I put floor in front: [[floor(3/2)d8]] I get an error, am I doing something wrong?

Floor is calculated after rolling dice. If you would like it to round down without floor use the following: [[((3/2)-0.5)d8]]

So, if I want to do this with something that increases every 6 levels, I would need to do something like this: [[((@Level/6)-(1/6))d6]]?

[[ ((@{Level}/6)-.5)d6 ]] The number of dice rolled is rounded up when a floating point number is supplied. [[(1.5)d6]] rolls 2d6, [[(1.499999)d6]] rolls 1d6. Here's a table that shows this: Level /6 -0.5 Rounded 1 0.17 -0.33 0 2 0.33 -0.17 0 3 0.50 0.00 0 4 0.67 0.17 0 5 0.83 0.33 0 6 1.00 0.50 1 7 1.17 0.67 1 8 1.33 0.83 1 9 1.50 1.00 1 10 1.67 1.17 1 11 1.83 1.33 1 12 2.00 1.50 2 13 2.17 1.67 2 14 2.33 1.83 2 15 2.50 2.00 2 16 2.67 2.17 2 17 2.83 2.33 2 18 3.00 2.50 3 19 3.17 2.67 3 20 3.33 2.83 3 So, you can see that the Rounded Column will go from rolling 0 dice to 1 die at 6th level, 2 dice at 12th level, 3 dice at 18th level, etc. If you didn't subtract the .5, you'd start rolling 1 die at 3rd level. Hope that helps!!

Thanks, that helps a lot.

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