How do I do multiples of the same roll with a flat?

I've been trying to crack this for weeks now, since the system I use makes a lot of the same rolls with the same flat added to each dice, but from as much as I found roll20 doesn't support that, making me have to re-do each roll separately. To give you a simple explanation, if I write this: /roll 2d1+3 The output will be: 1+1+3=5 The output I need is: (1+3)+(1+3)=8 Sadly no way of using the /roll command that I tried so far had any way of incorporating that. The mechanics require for me to see both the (X+Y)+(A+B) and their total sum.

You could do something like: /roll ?{Num dice|0}d1 + [[?{Num dice}*3]]

Scott C. said: You could do something like: /roll ?{Num dice|0}d1 + [[?{Num dice}*3]] If you could also explain how this command works that would be neat. Though I'm not sure if a command this long wouldn't actually be unhelpful.

Boom F. said: Scott C. said: You could do something like: /roll ?{Num dice|0}d1 + [[?{Num dice}*3]] If you could also explain how this command works that would be neat. Though I'm not sure if a command this long wouldn't actually be unhelpful. Basically if you type that (or make a macro). It will ask you the number of dice. if you enter 2 the result will be  2d1+ (2*3), and 3 will be 3d1 + (3*3). But then again you could also type /roll 2d1 + 2*3

If you could supply a little more information regarding the specific mechanics of the system, and the system name as well, we may be able to make some much more useful suggestions for you :) Roll20 is system agnostic so there are few things that can't be supported by the dice engine and some fancy maths.

Josh said: Boom F. said: Scott C. said: You could do something like: /roll ?{Num dice|0}d1 + [[?{Num dice}*3]] If you could also explain how this command works that would be neat. Though I'm not sure if a command this long wouldn't actually be unhelpful. Basically if you type that (or make a macro). It will ask you the number of dice. if you enter 2 the result will be  2d1+ (2*3), and 3 will be 3d1 + (3*3). But then again you could also type /roll 2d1 + 2*3 Yep, I was just throwing out a generic macro that you could modify for whatever your specific use case is. As Ziechael said though, there may be a better way that someone knows of if we know what you're trying to do.

Boom F. said: If you could also explain how this command works that would be neat. Check out: Roll Queries Inline Dice Rolls