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Seemingly Simple Success problem

1487093983

Edited 1487094093
So, I've been looking all over the forums and the dice wiki trying to figure this out. It seems like it should be super simple, so I apologize in advance for wasting everyone's time, but I'm stumped. I'm playing an engine with a success based dice system. It uses d4s, d6s, d8s, d10s, and d12s, but they all follow the same 3 rules for rolling. 1-Any dice with 5 or greater provides a success (this is simple to figure out, eg: 5d6>5) 2-Any dice that rolls its highest provides a success as well, meaning a single dice can provide 2 successes (I can easily do 5d6>6, but I don't know how to combine rules 1 and 2 to get multiple successes on a dice) 3-Any dice that rolls a double digit explodes (this is also easy, especially since it only applies to d10s and d12s) I'll admit my first attempt was simply 5d6>5>6, but this doesn't work. That seems obvious in retrospect. So, TLDR: how do I get one dice to provide 2 successes on a given roll?
Unfortunately, "double-successes" isn't a mechanic that Roll20's dice engine natively supports. You could create Rollable Tables to emulate dice rolls, e.g. to emulate 1d10: Table Item Weight 0 4 1 5 2 1 Alternatively, I wrote a few macros (for Exalted) that could be adapted for your situation, here .
Darn, that's what I was worried about. It seemed like a mechanic that, if not easily found, probably didn't exist. Thanks for the help! I'll take a look at the macros you linked to.