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[Earthdawn 4E] Adding Karma step

1494591421
Dougansf
Pro
Sheet Author
Thanks to Silvyre, we have this great macro to roll Earthdawns step chart. --Rolled|**[[ [[{1e3, 8}<[[{?{Step} - 11, 0}kh1 % 11]] + floor([[{?{Step} - 11, 0}kh1]] / 11)]]d20! + [[{2, 4, 5, 6, 7}=[[{?{Step}, 0}kh1 % 11]] + {1, 3}=[[{?{Step}, 0}kh1]] + {1e3, 3}=[[{?{Step} - 11, 0}kh1 % 11]] * 2]]d[[{{(?{Step} - 1) * 2, 4}kh1, {12}}kl1]]! + [[{1e3, 8}<[[{?{Step}, 0}kh1]] * (1 - {3, 6, 10}=[[{?{Step}, 0}kh1 % 11]] + {1, 4, 8}=[[{?{Step}, 0}kh1 % 11]])]]d[[10 - {4, 5, 8, 9}=[[{?{Step}, 0}kh1 % 11]] * 4]]! + [[{1e3, 8}<[[{?{Step}, 0}kh1]] * ({0, 5, 7, 9}=[[{?{Step}, 1}kh1 % 11]] + 2 * {6, 10}=[[{?{Step}, 0}kh1 % 11]])]]d8! - [[{1, 2}=[[{?{Step}, 0}kh1]] * (3 - [[{?{Step}, 0}kh1]])]] + ?{Karma #}d@{KarmaDie}! ]]** I've found that some creatures have a Karma Step that includes more than one die.  I was wondering if there was a way to change it to rolling the Karma step (therefor rolling on the step chart again) and adding it to the base roll.  It still needs to be able to spend multiple Karma at once.
1494597040
Silvyre
Forum Champion
Something like this? [[ [[{1e3, 8}<[[{?{Step} - 11, 0}kh1 % 11]] + floor([[{?{Step} - 11, 0}kh1]] / 11)]]d20! + [[{2, 4, 5, 6, 7}=[[{?{Step}, 0}kh1 % 11]] + {1, 3}=[[{?{Step}, 0}kh1]] + {1e3, 3}=[[{?{Step} - 11, 0}kh1 % 11]] * 2]]d[[{{(?{Step} - 1) * 2, 4}kh1, {12} }kl1]]! + [[{1e3, 8}<[[{?{Step}, 0}kh1]] * (1 - {3, 6, 10}=[[{?{Step}, 0}kh1 % 11]] + {1, 4, 8}=[[{?{Step}, 0}kh1 % 11]])]]d[[10 - {4, 5, 8, 9}=[[{?{Step}, 0}kh1 % 11]] * 4]]! + [[{1e3, 8}<[[{?{Step}, 0}kh1]] * ({0, 5, 7, 9}=[[{?{Step}, 1}kh1 % 11]] + 2 * {6, 10}=[[{?{Step}, 0}kh1 % 11]])]]d8! - [[{1, 2}=[[{?{Step}, 0}kh1]] * (3 - [[{?{Step}, 0}kh1]])]] + [[{1e3, 8}<[[{?{Karma|0} - 11, 0}kh1 % 11]] + floor([[{?{Karma} - 11, 0}kh1]] / 11)]]d20! + [[{2, 4, 5, 6, 7}=[[{?{Karma}, 0}kh1 % 11]] + {1, 3}=[[{?{Karma}, 0}kh1]] + {1e3, 3}=[[{?{Karma} - 11, 0}kh1 % 11]] * 2]]d[[{{(?{Karma} - 1) * 2, 4}kh1, {12} }kl1]]! + [[{1e3, 8}<[[{?{Karma}, 0}kh1]] * (1 - {3, 6, 10}=[[{?{Karma}, 0}kh1 % 11]] + {1, 4, 8}=[[{?{Karma}, 0}kh1 % 11]])]]d[[10 - {4, 5, 8, 9}=[[{?{Karma}, 0}kh1 % 11]] * 4]]! + [[{1e3, 8}<[[{?{Karma}, 0}kh1]] * ({0, 5, 7, 9}=[[{?{Karma}, 1}kh1 % 11]] + 2 * {6, 10}=[[{?{Karma}, 0}kh1 % 11]])]]d8! - [[{1, 2}=[[{?{Karma}, 0}kh1]] * (3 - [[{?{Karma}, 0}kh1]])]] ]]
1494598714
Dougansf
Pro
Sheet Author
Thanks.  That has allowed for karma to be a Step value. How can we make it so that you can choose to use multiple Karma?
1494614467

Edited 1494614487
Silvyre
Forum Champion
Would multiplying the number of dice typically rolled by the amount of Karma spent work? [[ [[{1e3, 8}<[[{?{Step} - 11, 0}kh1 % 11]] + floor([[{?{Step} - 11, 0}kh1]] / 11)]]d20! + [[{2, 4, 5, 6, 7}=[[{?{Step}, 0}kh1 % 11]] + {1, 3}=[[{?{Step}, 0}kh1]] + {1e3, 3}=[[{?{Step} - 11, 0}kh1 % 11]] * 2]]d[[{{(?{Step} - 1) * 2, 4}kh1, {12} }kl1]]! + [[{1e3, 8}<[[{?{Step}, 0}kh1]] * (1 - {3, 6, 10}=[[{?{Step}, 0}kh1 % 11]] + {1, 4, 8}=[[{?{Step}, 0}kh1 % 11]])]]d[[10 - {4, 5, 8, 9}=[[{?{Step}, 0}kh1 % 11]] * 4]]! + [[{1e3, 8}<[[{?{Step}, 0}kh1]] * ({0, 5, 7, 9}=[[{?{Step}, 1}kh1 % 11]] + 2 * {6, 10}=[[{?{Step}, 0}kh1 % 11]])]]d8! - [[{1, 2}=[[{?{Step}, 0}kh1]] * (3 - [[{?{Step}, 0}kh1]])]] + [ ?{Karma Spent|0} Karma spent] [[?{Karma Spent} * ({1e3, 8}<[[{ @{karma_step} - 11, 0}kh1 % 11]] + floor([[{@{karma_step} - 11, 0}kh1]] / 11))]]d20! + [[?{Karma Spent} * ({2, 4, 5, 6, 7}=[[{@{karma_step}, 0}kh1 % 11]] + {1, 3}=[[{@{karma_step}, 0}kh1]] + {1e3, 3}=[[{@{karma_step} - 11, 0}kh1 % 11]] * 2)]]d[[{{(@{karma_step} - 1) * 2, 4}kh1, {12} }kl1]]! + [[?{Karma Spent} * ({1e3, 8}<[[{@{karma_step}, 0}kh1]] * (1 - {3, 6, 10}=[[{@{karma_step}, 0}kh1 % 11]] + {1, 4, 8}=[[{@{karma_step}, 0}kh1 % 11]]))]]d[[10 - {4, 5, 8, 9}=[[{@{karma_step}, 0}kh1 % 11]] * 4]]! + [[?{Karma Spent} * ({1e3, 8}<[[{@{karma_step}, 0}kh1]] * ({0, 5, 7, 9}=[[{@{karma_step}, 1}kh1 % 11]] + 2 * {6, 10}=[[{@{karma_step}, 0}kh1 % 11]]))]]d8! - [[?{Karma Spent} * ({1, 2}=[[{@{karma_step}, 0}kh1]] * (3 - [[{@{karma_step}, 0}kh1]]))]] ]]
1494615783
Dougansf
Pro
Sheet Author
That seems to do it! Thanks again! (Now to replace every roll on my character sheet again...)
1494616033
Silvyre
Forum Champion
Great, happy to help!