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How to count dice over a certain a number?

February 28 (11 years ago)
Is there anyway of counting dice only over a certain number? 1-2=0 3-4=1 5-6=2.
You could make a six-sided roll-able table and have the "sides" go 0,0,1,1,2,2.

https://wiki.roll20.net/Card_Decks_and_Rollable_Ta...


February 28 (11 years ago)
roll a 3 sided die instead of a six 1=0 2=1 3=0 it's a no brainer
February 28 (11 years ago)
1 and 6 are crits...Not a no brainer.
I realize it's the more complicated option, but with the rollable tables you would get your six sided die, and if you use images for the 'faces' you could make 0 and 2 different to illustrate the Crit.
March 01 (11 years ago)
Ok So im working on the table. Almost got it how I want. On a roll 6 I get to roll another die. Is there anyway of doing this with a table? Besides that it looks like I just have crit next to 1 and 6 that equal 0 and 2. So I can tell they critted.
I don't know if it'd work or not so you have to test, but you may be able to combine rollable tables and exploding dice.(If you roll max value and it rolls again)
https://wiki.roll20.net/Dice_Reference#Exploding_D...

/roll 1t[table-name]!
March 03 (11 years ago)

Edited March 03 (11 years ago)
GiGs
Pro
Sheet Author
API Scripter
Sadly tables do not support exploding dice. If you get a 6 on your result, you'll need to make a new table roll.
What you could do is decide how many explosions to want, and then create a table with the full range of possibilities using the weighting entry.

For instance, if on a roll of 6, you get an extra d6 added to it, that would look like this:
ResultWeighting
16
26
36
46
56
71
81
91
101
111
121

I know that's not how it works in your game; this example is just to illustrate the concept.
March 03 (11 years ago)
Ya except if you get multiple 6s it wouldnt work...Ill just keep doing what im doing I suppose.
March 03 (11 years ago)
Well could go three steps into it, to 66x, that's 18 possibilities. Should be more or less easy enough to do.

IF someone actually rolls a 666 on that table... (1 in 216 rolls), they just have to hit the macro again. Or you go 4 steps in. 6666 is a 1 in 1296 chance, that should be good enough.

March 03 (11 years ago)
Ya. Ill think about it. 1296 entries would take some time. lol
March 04 (11 years ago)
GiGs
Pro
Sheet Author
API Scripter
You dont actually need 1296 entries. For example, if you were rolling 3d6 and adding then together, there are 216 different ways the dice can fall, but you only need 16 different table entries.
Describe how the dice work in your game and I'll tell you how to make a short table that represents that.