VtM 5 edition macro?

I just need something basic  is a /r Xd10>6 but I need for it to add +2 successes for every 2 10s on the roll ex:   9, 3, 1, 10, 6 = 3 successes  10, 3, 1, 10, 6 = 5 successes  if someone has asked for (or done) this before please link me to it, I have been unable to found it.

Unfortunately the basic macro system in roll20 cant add extra successes on 10 the way you want. If you were a roll20 Pro user, a script like power Cards could do it, but at the basic level you cant. The best you can do is have the dice roll printed out in ascending or descending order, so the 10s are all grouped together, so you can easily calculate them yourself. This would do that: /r ?{Number of Dice?|1}d10>6sd sd = sort descending; if you want to sort ascending, change the sd  at the end to sa .

oh... ok thanks by the help anyway I will see if I can get a pro account eventually

While it wouldn't print the number of successes for you, you could set critical strike at 6 and then all successes would be highlighted in green. [[1d10cs>6]] The only issue with doing that is you need to repeat that for each die rolled.  You could set up a macro query to ask how many dice to roll.  This example stops at 3, but you can take it however far you would need. ?{Dice?|1,[[1d10cs>6]]|2,[[1d10cs>6]] [[1d10cs>6]]|3,[[1d10cs>6]] [[1d10cs>6]] [[1d10cs>6]]} Another option would be to just make a macro with the max number of dice you foresee anyone rolling, and making a rule that if you are rolling less, you take the first dice rolled in order up to the number you needed.  If the number needed for success ever changes or can be different between players, then you could set an attribute on character sheets and reference that in the macro for the cs value.  Hope something in this rambling makes sense and helps a little. Edit:  I didn't pay enough attention to G G's post.  Having them sorted is probably better than what I was thinking.