elemental adept macro

In fifth edition dungeons and dragons there is a feat that among other things allows you to turn all 1s on a roll with many dice into 2s. I need a way to write an if 1 then 2 statement but after looking at the dice reference page the closest I got was if 1 then reroll. Help?

There are two main ways to handle this: 1)  Rollable Table -- You can set up a rollable table with all the values of the die you need, but with no 1 and with 2 having a weight of 2. 2) Group statements -- you can use a formula of the type [[ {1d20, 2d1}kh1 ]] to give you a minimum of 2.

Okay here is my current macro: /roll {1d6,2d1,1d6,2d1,1d6,2d1,1d6,2d1,1d6,2d1,1d6,2d1,1d6,2d1,1d6,2d1}kh8. It isn't pretty but it rolls 8d6 and 1s are replaced with 2s. In this dungeons and dragons game in addition to being able to turn all 1s into 2s I can reroll four dice of my choosing every time I rolI and I always choose to reroll numbers that are 3 or lower. I found the reroll once section on the dice reference page and initially thought of doing something like: /roll {1d6ro<3,2d1,1d6ro<3,2d1,1d6<ro3,2d1,1d6<ro3,2d1,1d6,2d1,1d6,2d1,1d6,2d1,1d6,2d1}kh8 but the problem with this macro is that if these first four roll over 3 then I would have wasted my rerolls. Help?

I assume that my current structure will not allow me to implement this addition but I don't know how to restructure it to make it work.

The problem stated clearly: I am rolling 8 times There is a 50% chance any roll would prompt a reroll I can reroll a maximum of 4 times I can only reroll the original 8 rolls (no rerolling rerolls) If there aren't 4 original rolls that need a reroll all additional rerolls need to be wasted This needs to fit with one of the two provided if 1 then 2 statements

There are no if/then statements without getting into scripting. For your basic feat effect, you need /roll {1d6, 2d1}kh1  + {1d6, 2d1}kh1  + {1d6, 2d1}kh1  + {1d6, 2d1}kh1  + {1d6, 2d1}kh1  + {1d6, 2d1}kh1  + {1d6, 2d1}kh1  + {1d6, 2d1}kh1 Do your discretionary rerolls manually, perhaps with a macro button prompt.

As you are a Pro user, if you are the GM you could do this with a script. The Power Cards API script might be able to do it - I'd ask in that thread. 

In case anyone might be interested... To solve this issue in my came, I use a modified version of Adept, where 1s are re-rolled.  My simple script example is: [[(?{Spell Slot Level|3})d10r<1 ]] or for cantrips with damage driven by caster level I use: [[[[ 1+floor((@{selected|level}+1)/6) ]]d8r<1 ]] The formulas are not exactly as the players describe the feat, but this is simple, and I believe more worthy of a feat use. Also, this solution does NOT require a Pro subscription. Cheers, Barry Smith