Hi, need help for a simple macro

Hi, and sorry if my english is not really good. I'm creating a rpg set of rules that i want to test on roll20 but i have troubles to create a macro. I need to roll Xd10 and count the nomber of dice under a specific value and reroll the 10 (and count them as a succes, for my game 10=0). To do that, i used this macro: /r {3d10r10}<4 The macro works but i dont know how to consider the 10 as succeses. Does anyone know if i can do that please ? Thanks for reading me guys.

It would be easier to do a number higher as Roll20 dice consider the 10 to be a 10, why not bump up all the difficulties by one and have 1 be the reroll <a href="https://wiki.roll20.net/Dice_Reference" rel="nofollow">https://wiki.roll20.net/Dice_Reference</a>

So, the short answer is, you probably need a script for that. The slightly longer answer is, change your dice logic, so that you count dice above a value as successes, then also use exploding dice for 10s.&nbsp; so now your dice roll becomes /r {3d10!}&gt;7 Or alternatively make 1s your exploding dice and still keep the under a number logic. Hope this helps

Thx for the answers. I'll have to think about it. I like my rule for pen and paper but it's not efficient on Roll20. i'll see what i can find about script :) and use Evil's solution during the process. Thx again

You can set the die to explode on any value, the problem is setting the dice result of 10 to 0.&nbsp; You can simulate it by rolling 1d10-1, in which case the range of results is 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, exactly the same as a d10 where you are treating 10 as 0. Then the roll you listed above r {3d10r10}&lt;4 becomes /r {3d10!1-1}&lt;4 Breaking this down: This is a group roll {3d10-1}&lt;4 any modifier here is applied to each die individually. So if you rolled 6, 5, and 2, they would be treated as 5, 4, and 1, and you'd get 2 successes, This part 3d10!1 Says explode (roll again) on results of 1. This is before the modifier of -1 gets applied. So its actually rolling again on results of 0, which is your 10 result. So the roll&nbsp; /r {3d10!1-1}&lt;4 does seem to do what you want. The dice displayed in chat wont match the rolls (because of the -1), so it might look weird but it is accurate.

Hi Gigs and thx a lot for your answer