Rounding and summing for a roll maccro

Hello ! I've been looking up for quite a time now, but I can't find how to do this : Let's say I have 4 attributes and one ability. I want that ability to use the sum of the 4 attributes, divided by 2 rounded down, and roll it as d6>5. What I've got is : /r floor((@attribute1+@attribute2+@attribute3+@attribute4)/2)d6>5 I've tryed severals syntaxes but every times it fails to give me the result I expect. Any clue? Thanks :)

I assume you are using @{attribute} and not @attribute? If so, its a good idea to wrap this calculation in inline roll brackets, like so /r [[floor((@{attribute1}+@{attribute2}+@{attribute3}+@{attribute4})/2)]]d6>5

Yes, I was using @{attribute} :) But your syntax worked just great, thanks a lot !

you're welcome :)