Any way to force a minimum roll on a d20?

a noob on roll20 sorry, trying to work out if it's possible to force a minimum roll on a check? I've got stealth +11 but a feat that changes any rolls under 10 to be 10.  So I need a roll of (if /roll d20 < 9 then roll = 10) + 11 Any way to do that?

Andrew C. said: a noob on roll20 sorry, trying to work out if it's possible to force a minimum roll on a check? I've got stealth +11 but a feat that changes any rolls under 10 to be 10.&nbsp; So I need a roll of (if /roll d20 &lt; 9 then roll = 10) + 11 Any way to do that? Hello Andrew. You might want to look into 'Keep Highest 1' / 'Keep Lowest 1' or 'Drop Highest 1' / 'Drop Lowest 1' There is a good post here describing it:&nbsp; <a href="https://app.roll20.net/forum/post/1517148/slug%7D" rel="nofollow">https://app.roll20.net/forum/post/1517148/slug%7D</a> The base premist is that you can pick the highest / lowest of two numbers by writing {{3,5}k1} Type the above into the chat and play around with it. Remember to wrap it in [[ ]] to make it calculate. Both sides has to be either a math expression or a roll, so if you want a roll it should look like: {{1d20, 0d0+10}kh1} + 11 This will take the highest of either 1d20, or 10, and then add 11. Good luck coding! :)

That is awesome, I did see the keep highest/lowest but couldn't think of how to use that, but the 0d0+10 is great idea. Thanks very much!!

1d20r9&nbsp; will make it reroll the d20 until higher than 9. it will skew the average results but it's there. You could also just roll 1d9+11

Ryn said: 1d20r9&nbsp; will make it reroll the d20 until higher than 9. it will skew the average results but it's there. You could also just roll 1d9+11 Both of those provide different odds than what OP wants. They provide equal chance of getting a 10, 11, 12, etc. The OPs roll gives a massive increase of the chance of rolling 10, rolls of 1-9 are still kept, but they equal 10.

EDIT: Nevermind. I missed that Peter already answered this.