Rolling d10s where 10s count as 2 successes instead of exploding

Hello!

I'm looking for some Roll Mechanics help!

In our custom Exalted campaign, we use a custom dice mechanic. Instead of 10s exploding and rolling an additional dice, we simply count 10s as two successes and move on.

so, if one were to type  /roll 3d10>6s    and got an output of {1,8,10} we would count 3 successes. 

Right now, we have to manually re-sum the 10s because we can't figure out how to trick Roll20 into thinking this way. 

Does anyone know a way to perform this is a command? Bonus points if we can turn this into a macro!

Thanks!

It is possible to do this in a roundabout way, by taking advantage of the failure point modifier. In roll20, you can count for successes, luke >6, but you can also count failures by doing f<5.

/roll ?{Number of Dice|1} + ?{Number of Dice}d10>10f<5

So this macro asks you how many dice you are rolling. If rolling 3, the above macro would become

/roll 3 + 3d10>10f<5

So, this counts rolls of 10 or more as a success, worth one point. Rolls of 6-9 are neither success nor failure, so count as zero points. Rolls of below 6 count as failures worth -1 point.

Then we add 1 point per die (the 3 at the start) to bump them up to 0, 1, and 2 points respectively. And that gets you the exalted rolls.

If you say what you mean by performing this as a command or turning into a macro, we can do that for you. But in fact any text you type in chat is already a macro, you just need to save it as one.

Thanks!

I actually found a thread further below that recommended creating a rollable table, and I think I'll propose both to the GM and see which direction he wants to go. 

Rollable-table where rows 1-5 are a "0", rows 6-9 are a "1", and row 10 is a "2".  naming it "d10" means we'd just use the command "/roll Xt[d10]" to roll on the table X times, and sum the returned values.

That would work too!