Help reusing roll in a macro

Hi! We use a custom D100 system and i would like to find/write a macro roll for it: When a player roll a dice for attacking, the damages will depends on "how much" he success like: My player roll 1d100<70, 33, he success by 70-33 = 37. Now from this 37 we count how much "5" we can fit in it, the answer is 7 (7*5=35) so his success rate is 7 and it'll add 7 to his damages. So i'm searching for a macro to do this automatically, like my player roll "1d100<70" and if the result is 37 the script should output something like:"37, success rate=7" In simple maths, i would like to do something like: - My player use the macro lire "/rs {SkillLevel} (which is 70 in my previous instance) - My player roll, i store the variable {RollResult} - Maths: {SuccessRate}=ROUNDDOWN(({SkillLevel}-{RollResult})/5) - Output: "Result: {RollResult}, success/fail by {SuccessRate}" Do anybody know a macro that can do something similar or any tutorial that would help me to make this? I already read the "Reusing Rolls" wiki page but i'm not good enough with macro to make mine with this (i don't understand how to use & store variable in a macro). Thanks!

Something like this should do the job: &{template:default} {{name=Skill Roll}} [[ floor(abs({[[1d100]]-?{Skill Level|37},0}kl1/5)) ]] {{Roll Result=$[[0]] vs ?{Skill Level}}} {{Success Rate=$[[1]]}} You might want to change the default Skill Level, or change it to an @{Attribute} reference if it's recorded on a character sheet. You could also add some success/failure coloring if you'd like, change the roll to: [[ floor(abs({[[1d100cf>?{Skill Level|37}cs<?{Skill Level}]]-?{Skill Level},0}kl1/5)) ]] Green for rolling under, red for rolling over, and blue for exact. edit - corrected the math

M.J  said: Now from this 37 we count how much "5" we can fit in it, the answer is 7 (7*5=35) so his success rate is 7 and it'll add 7 to his damages. Just to check if 0s are valid, if a character has a skill of 40, and rolled a 37, what is the success rate?

GiGs said: M.J  said: Now from this 37 we count how much "5" we can fit in it, the answer is 7 (7*5=35) so his success rate is 7 and it'll add 7 to his damages. Just to check if 0s are valid, if a character has a skill of 40, and rolled a 37, what is the success rate? It's 0, it's a success but without any bonus.

Great - was just checking because if the minimum was 1 (I have seen some systems that work like this), Oosh's macro would need some tweaking.

Oosh said: Something like this should do the job: &{template:default} {{name=Skill Roll}} [[ floor(abs({[[1d100]]-?{Skill Level|37},0}kl1/5)) ]] {{Roll Result=$[[0]] vs ?{Skill Level}}} {{Success Rate=$[[1]]}} You might want to change the default Skill Level, or change it to an @{Attribute} reference if it's recorded on a character sheet. You could also add some success/failure coloring if you'd like, change the roll to: [[ floor(abs({[[1d100cf>?{Skill Level|37}cs<?{Skill Level}]]-?{Skill Level},0}kl1/5)) ]] Green for rolling under, red for rolling over, and blue for exact. edit - corrected the math Thanks! But with this i need to add all their skills with skill level on their character sheet & they have to roll using one different macro for each skill right? Is there a way to make this like a command with an arg? like "/rs {skilllevel} and they just enter their skill level?

This part: ?{Skill Level|37} is a query. It is exactly what you want. It is a popup form that lets players enter a skill value (the |37 part says 37 will be inserted by default, you can change the number to something else).

Oh yes i just tried, it works like a charm! Many thanks for all! Is there a way to color the window & change the title depending on if it's a success or a fail?