Thanks for the link Andreas. Firewinds - I think the italics part and bold part is part of how the template is built. Anything to the right of the == sign (the $[[2]] in your case) is supposed to just be a die result; where text to the left of the == sign is the label for what is being rolled (and automatically bolded by the template)...default formatting that can't be changed. I'm not sure, but think that is it. Also, as a side note, by doing rolls like this you can refer to them multiple times in the same message. The following macro will put the result of the d20 in the "Rolls a D20" line, and at the end of the second line (after your query output). :&{template:default} [[ [[1d20]] + [[?{modifier|0}]] ]] {{name= Skill Check }} {{ Rolls a D20 $[[0]] + $[[1]] Skill Points ==$[[2]] **TOTAL** }} {{for ?{reason|no reason|Acrobatics-Balance|Animal Handling-Farm|Blacksmith-Repair|Body Constitution|Carpentry|Charisma-Charm|Deception|Domestic Crafts-Food-Sewing|Fighting|History-Knowledge-Intelligence|Initiative|Intimidation|Medicine-Potions|Movement|Music|Perception-Investigation|Performance-Acting|religion-Magic|Ride Mount|Sailing|Stealth|Shooting-Ranged Weapons|Strength|Survival-Nature-Fishing }. $[[0]]}} But as to how it works, I think you make the rolls prior to displaying anything in the chat window roll template (i.e. prior to any template formatting), and can call the result with the $[[X]] reference at any point in the macro (so you can reuse rolls multiple times relying on a specific roll) As a note: this only works within a single macro...AFAIK it will not transfer down to nested macros, or be able to be used outside of that specific macro call for referencing those initial rolls. example: [[ [[1d20]] [[1d12]] [[1d6]] [[1d20]] ]] ... would give you 4 die results - $[[0]], $[[1]], $[[2]], and $[[3]] You could do math later with those die results all in the same roll template and same macro. {{ $[[0]] + $[[2]]==$[[4]]}} {{$[[0]] + $[[1]] + $[[3]]==$[[5]]}} {{$[[4]] + $[[5]]==$[[6]]}} Lets say the results were a 13, 8, 3, 9 (for a d20, d12, d6, d20) the next line would equate to (13 + 3 = 16) where $[[4]] = 16 and the next line (13 + 8 = 21) where $[[5]] = 21 and last line (16 + 21 = 37) where $[[6]] =37