It is, kind of, but not in obvious way. You can count failures as well as successes, so each die gives -1, 0, or 1 success. If you then add the number of dice, you get 0, 1, or 2 successes, which is what you want. So you can do it this way: /roll ?{number|1}d6>6f<3 + ?{number} and maybe have it look more presentable &{template:default} {{name=?{number|1} dice}} {{Successes= [[?{number|1}d6>6f<3 + ?{number}]] }} You could rearrange this to show what you want - the idea is to hide the complicated roll inside an inline roll.
