D&D 4e Character Sheet Macro Problem

I am using the D&D 4e character sheet template. I have this macro as a monster macro: /emas @{selected|token_name} sprays a stream of fire [[d20+4]] to hit vs @{target|token_name}'s Reflex @{target|ref} and deals [[3d6]] fire damage. When I run it I get this: Fire Beetle sprays a stream of fire 24 to hit vs Artanis Talvir's Reflex 10+floor(5/2)+floor((19-10)/2)+0+1+0+0+0+0 and deals 13 fire damage. So instead of getting just one number for reflex, I am getting the reflex score calculation. How do I change so I just get the reflex score?

Put the @{target|ref} inside [[ ]] and that SHOULD fix things. I'm 90% sure :>

That fixed it. Now a more difficult question: I want to change a character's attack and damage based on whether they are bloodied or not. I am tried to implement the technique given here but there are a few things wrong I can't figure out. Firstly, my global macro (Is_bloodied) works and outputs a 0 if not bloodied and a 1 if bloodied as a roll. When I try to execute the macro inside another macro, things get wonky. Here is the code: /me uses @{power-3-name} at @{target|target1|token_name} [[1d20+(#Is_bloodied*1)+@{power-3-attack}]] vs @{power-3-def} Hit: [[(1*@{power-3-weapon-num-dice})d@{power-3-weapon-dice}+@{power-3-damage}+(#Is_bloodied*2)]] Damage and deals an additional 4 to @{target|target2|token_name}

Instead of a macro inside a macro, use an attribute of 'is_bloodied' and your equation should (at first skim) work as desired.

So how do I set up the attribute?

Open your character journal, go to the Attributes & Abilities tab, click +ADD on the Attributes side of the screen, rename the Untitled attribute to 'is_bloodied' and then give it a value of 0 or 1.

Thank you. Is there a way to automate that so that the 0 changes to 1 whenever the character is bloodied?

If you want it automated, another way would be to use HP divided by HP_Max (using whatever attributes your character sheet uses to track HP and maximum HP), in an equation that resolves to 0 or 1 in the end. That sort of math is NOT my forte, but I know there's others around here who can do it.

Thanks.