Macro to restrict the maximum modifier per level!

Hello I am needing to create a macro to cast spells. Example Cure Light Wounds (D&D), it is 1d8 +1/level a maximum of +5. I created the attribute "Level" and the macro: # CuraLeve /r 1d8 + @{Level} If the character is at level 6 or more, will add +6 I was wondering if anyone knows how I can restrict the maximum +5? Excuse the spelling, I'm using Google Translator, I'm Brazilian. Thank you all! ;)

Here you go: /r 1d8+ Level-(Level-Maxlevel)*[[(floor(1/(floor(Level/Maxlevel)+1))-1)*(floor(1/(floor(Level/Maxlevel)+1))-1)]] Note: Danilo came up with this in this thread: <a href="https://app.roll20.net/forum/post/328661/shocking-grasp#post-332640" rel="nofollow">https://app.roll20.net/forum/post/328661/shocking-grasp#post-332640</a> - Gauss Edit: I did not want to put attribute values in everywhere so I just used the words. Level should be an Attribute while Maxlevel can be just a number or an attribute (your choice, I suggest number).

Thanks for the help ! Did not understand the function implemented but solved my problem . :) know where I can learn about this function ?

It is not a Roll20 function so much as a mathematics function with one Roll20 function. Here are some examples to show you what it does (for the purposes of this I am removing the inline brackets since they are for Roll20 and not math). I will bold the terms that are being simplified.: Example 1: Level is 9 and Maxlevel is 5 9-( 9-5 )*(floor(1/( floor(9/5) +1))-1)*(floor(1/ (floor(9/5) +1))-1) = 9-(4)*(floor(1/( 1+1 ))-1)*(floor(1/( 1+1 ))-1) = 9-(4)*( floor(1/(2) )-1)*( floor(1/(2) )-1) = 9-(4)*( 0-1 )*( 0-1 ) = 9-(4)* (-1)*(-1) = 9- (4)*1 = 9-(4) = 5 As you can see, the terms with floor (round down) came out to -1. When -1*-1 the result is 1. This will happen every time Level is greater than Maxlevel. When 1 is multiplied with (Level-Maxlevel) it allows (Level-Maxlevel) to stay intact (no change). Then (Level-Maxlevel) subtracts from Level to bring it down to the maximum value. Example 2: Level is 6 and Maxlevel is 10 6-( 6-10 )*(floor(1/( floor(6/10) +1))-1)*(floor(1/( floor(6/10) +1))-1) = 6-(-4)*(floor(1/( 0+1 ))-1)*(floor(1/( 0+1 ))-1) = 6-(-4)*( floor(1/(1)) -1)*( floor(1/(1)) -1) = 6-(-4)*( 1-1 )*( 1-1 ) = 6- (-4)*(0)*(0) = 6-0 = 6 As you can see, the terms with floor (round down) came out to 0. This will happen every time Level is less than Maxlevel. When 0 is multiplied against (Level-Maxlevel) the result is zero which takes it out of the equation leaving just the first "Level". Summary: The two terms with Floor in them are a 0 or 1 switch. If 0 they remove the (Level-Maxlevel) term. If 1 they allow the (Level-Maxlevel) term to stay intact. If that term stays intact it will be subtracted from "Level" which will bring "Level" down to the maximum value. I hope that explains how it works. :) - Gauss

that is devilishly fiendish. I like it

Noting that the purpose of the two identical "floor" terms is just to change a -1 into a +1 through multiplication, the statement can be simplified as follows: /r 1d8+ Level + (Level-Maxlevel)*[[(floor(1/(floor(Level/Maxlevel)+1))-1)]] Or, alternatively: /r 1d8+ Level-( Maxlevel-Level )*[[(floor(1/(floor(Level/Maxlevel)+1))-1)]] Both of these will save a miniscule bit of processing time, but more importantly, they're shorter, so there's less chance of making a typo :) -David

David, I felt there was a simpler method, thank you for demonstrating it. :) I will let Danilo (he wrote the original method) know about the simpler method. - Gauss

That's great David =D thanks for this =D