Calculating Macros

Hi guys! This is my first post in this forum, so I want to introduce myself: My name is Chris, 33 years old. I'm from Germany (Bavaria to be precise) and have been playing p&p and LARP for roughly 20 years. Me and my group have settled to roll20 due to the ongoing pandemic, and I vounteered to manage the softeware side of things. As I recently started playing arround with macros I encountered a problem. As we have simplyfied the dice-rolling-mechanism in our ruleset to use only one instead of 3d20 to be more convenient and beginnerfriendly we came up with this formula: [1d20 < (attribute1+attribute2+attribute3)/3 ] = success As I understood the syntax the macro utilising an inline-roll should theoretically look like this: [[1d20< (@{MU}+@{GE}+@{KO})/3]]  The formula above uses the attrubite-names from the German "Das Schwarze Auge"-Charsheet. If I now execute the macro like this the outcome is always 1, e.g. success. Here comes the question: Is it possible to perform what I want the macro to do with some code-wizardry, or do I have to do the math myself? thanks for helping out, best regards, Chris

I think that should work, but you will likely need another set of brackets. [[1d20<[[(@{MU}+@{GE}+@{KO})/3]]]] The inner set of brackets should force the addition/division to be resolved to a number before comparing it to the d20 roll.

Thank you very much! that works just fine! is there a way to automatically upround the resolved equation to a straight number?

I just figured out myself, that there is the "ceil" function. The complete expression looks like this now: /w gm &{template:default} {{name=Fulminictus}} {{ ?{Variante| Schaden, Erfolg:[[1d20<[[ceil((@{MU}+@{GE}+@{KO})/3)]]]]=[[2d6]]TP| Welle der Schmerzen, Erfolg:[[1d20<[[ceil((@{MU}+@{GE}+@{KO})/3)]]]]=[[2d6+15]]TP-A| } }}