Target number roll, maximum number rolled/exploding die count as two success instead of rerolling

Topic.  Let's say I roll 6d10, success on 5 or higher, and 10 will be counted as two successes. The formula for the first part is (/r 6d10>5) right? but how do I make it so every 10 counts as two successes instead?

This is tricky, but as long as nothing special happaens on 1 you can do this in a sneaky way by counting failures . Here are two ways to show this: /r 6d10>10<4 + 6 [[6d10>10<4 + 6]] The method: in failure rolls, you get 1, 0, or -1 per die. But you want 2, 1, or 0. So, you use the failure method but add the number of dice, which gets the right number of successes per die. If the number of dice vary you need to include the calculation twice - forst with the number of d10, then again as a flat bonus.