Replacing rolls with number X

Hi all, I've recently (think november last year) started playing DND here on this site. Right now I'm in a campaign playing a sorceress with the Elemental Adept feat. This means that every 1 I roll for element X is replaced by a two. Now I'm wondering how I can achieve this in a macro. For example take Fireball with 8d6 of dmg. Would I need to add 8 2s and say keep the highest 3? Or is there an easier to way to achieve this. I do have a small macro for doing this, but need to scale this to other spells. Current macro: /roll {[[1d6]],2 }kh1

The only way I know is to repeat what you already have multiple times.

I would create a Rollable Table named d6min2 with: Value : Weight 6 : 1 5 : 1 4 : 1 3 : 1 2 : 2 Then roll it like: [[8t[d6min2] ]] or /roll 8t[d6min2] That will give you the right distribution and behave like regular dice. If you need to know that a 1 was rolled but replaced with a 2, you can instead weight 2 as 1, and add an entry 2 [1] with weight 1:

Gah, I always forget that method

=D  I actually have a script for creating these called WeightedDice. =D

thx for the help :D This is exactly what I was looking for :)