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Exploding dice continuum problem

October 11 (5 years ago)

If I carry out an exploding die roll are there forbidden numbers


For example if I roll 1d6 exploding you can never get a multiple of 6 for the final result e.g. {6,12,18,...} 


One solution would be to set the lowest number of the die to zero, instead of one, but I don't think that is possible using the standard roll20 dice roller?

October 11 (5 years ago)
GiGs
Pro
Sheet Author
API Scripter

If you use the penetrating exploding dice modifier, any exploding dice have a -1 applied to them. it looks like this:

/roll 1d6!p


October 12 (5 years ago)

Thanks I will give it a go.

To scale it from zero I can do the following

 /roll 1d6!p-1

 However it won't work for multiple dice 3d6!p-1 instead I will have to put the roll formulae in long hand, like this.

/roll (1d6!p-1)+(1d6!p-1)+(1d6!p-1)
October 12 (5 years ago)
GiGs
Pro
Sheet Author
API Scripter

You can also do

/roll 3d6!p-3

It'll get the same total

But do you really need a -1 on the first roll? Most games that apply a -1 apply it only to the exploding dice. If you roll 1d6-1, you cant get a natural 6.