Help with a macro

Can anyone tell me why this macro works: [[(10-((@{Physical-Dmg}/3)))d6>5]] while this one with the added "floor" in it doesn't: [[(10-(floor(@{Physical-Dmg}/3)))d6>5]] but this one with which is the same as the above minus the d6>5 also works: [[(10-(floor(@{Physical-Dmg}/3)))]]

Because dice get rolled before floor gets triggered. It's the order of operations macros use.

however due to how the system handles fractional dice there is a solution that you can use. since your macro is a value divided by 3 and you want to always round down you'll just add into it after the division "-0.66" fractional dice are always rounded up so if you want to round down you have to subtract out the largest fractional for any given number. So if your equation would have normally given you a result of 3d6 it would instead now give 2.33d6 which will roll as 3d6 still, and likewise if the result was normally 3.66d6 it would have rolled 4d6 but will now result as 3d6

Chell said: fractional dice are always rounded up No, they are rounded to the nearest whole number (0.5 rounding to 1)

It works if I write it like this tough: /r [[(10-(floor(@{Physical-Dmg}/3)))]]d6>5

Brian said: Chell said: fractional dice are always rounded up No, they are rounded to the nearest whole number (0.5 rounding to 1) oops >.< sorry about that... so it should be -0.33 then [[(10-((@{Physical-Dmg}/3)-0.33))d6>5]]

My ultimate goal would be to have this macro in the "wound" attribute: [[(((@{Physical-Dmg}/3)-0.33))+(((@{Stun-Dmg}/3)-0.33))]] and then reference the "wound" attribute in another macro like so: [[(@{Agility}+@{Pistol}-@{wound})d6>5]] Im aware that inline rolls cannot be nested but can you guys see a work around for this. Essentially I would like the physical and stun damage wounds to be calculated in the wound attribute and then be able to use it within my other macros. I'm affraid it can only be done with api...

Just take the square brackets out of the @{wound} attribute; there's no need to have the attribute be an inline roll.